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Jawaban Soal Asas Black (Post 12 Feb 2013)

Sabtu, 20 April 2013

1. Diketahui :
T2=200C
m2 = 2000g = 2kg
T1=900C
Tc=620C
c1,2 = 4200 J/Kg0C

Ditanya :
m= ?

Jawab :
Q= Q2
m1 .  c1 . (T1-Tc)= m2 . c2 . (Tc-T2)
m1 .  4200 J/Kg0C . (900C-620C)= 2kg .  4200 J/Kg0C . (620C-200C)
m1 . 4200 J/Kg0C . (280C)= 2kg . 4200 J/Kg0C . (420C)
m . (280C)= 2kg .  (420C)
m1 . (280C)= 84kg0C
m = 84kg0C /  280C
m1 = 3kg

2.Diketahui :
T2=200C
m1 = 4kg
T1=1000C
Tc=520C
c1,2 = 4200 J/Kg0C

Ditanya :
m2 = ?

Jawab :
Q1 = Q2
m1 . c1 . (T1-Tc)= m2 . c2 . (Tc-T2)
4kg . 4200 J/Kg0C . (1000C-520C)= m2 . 4200 J/Kg0C . (520C-200C)
4kg . 4200 J/Kg0C . (480C)= m2 . 4200 J/Kg0C . (320C)
4kg  . (480C)= m2 . (320C)
4kg  . (480C)= 320C . m2
m = 4kg . (480C) 320C
m = 6kg


3. Diketahui :
T2=300C
m2 = 2kg
T1=600C
m1 = 2Kg
c1,2 = 4200 J/Kg0C

Ditanya :
Tc=.....0C

Jawab :
Q1 = Q2
m1 . c1 . (T1-Tc)= m2 . c2 . (Tc-T2)
2Kg . 4200 J/Kg0C . (600C-Tc0C)= 2kg . 4200 J/Kg0C . (Tc0C-300C)
2Kg .  (600C-Tc0C)= 2kg .(Tc0C-300C)
120Kg0C-2kgTc0C= 2kg Tc0C-60kg0C 
120Kg0C + 600kgC = 2kg Tc0C + 2kgTc0C
180Kg0C = 4Tc0kg
Tc = 180Kg0C / 4kg
Tc = 450C


4. Diketahui :
T2=100C
m2 = 30kg
T1=900C
m1 = 10Kg
c1,2 = 4200 J/Kg0C

Ditanya :
Tc=.....0C

Jawab :
Q1 = Q2
m1 . c1 . (T1-Tc)= m2 . c2 . (Tc-T2)
10Kg . 4200 J/Kg0C . (900C-Tc0C)= 30kg . 4200 J/Kg0C . (Tc0C-100C)
10Kg . (900C-Tc0C)= 30kg .(Tc0C-100C)
900Kg0C-10kgTc0C= 30kg Tc0C-300kg0C
900Kg0C + 3000kgC = 30kg Tc0C + 10kgTc0C
1200Kg0C = 40Tc0kg
Tc = 1200Kg0C / 4kg
Tc = 300C


5. Diketahui :
T2=100C
m1 = 150kg
T1=900C
Tc=400C
c1,2 = 4200 J/Kg0C

Ditanya :
m2 = ?

Jawab :
Q1 = Q2
m1 . c1 . (T1-Tc)= m2 . c2 . (Tc-T2)
150kg . 4200 J/Kg0C . (900C-400C)= m2 . 4200 J/Kg0C . (400C-100C)
150kg . 4200 J/Kg0C . (500C)= m2 . 4200 J/Kg0C . (300C)
150kg . (500C)= m2 . (300C)
150kg . (500C)= 300C . m2
m2 = 150kg . (500C) / 300C
m2 = 250kg


6. Diketahui :
T2=100C
m2 = 0,52kg
T1=900C
m1 = 0,1Kg
c1 = 380 J/Kg0C
c2 = 4200 J/Kg0C

Ditanya :
Tc=.....0C

Jawab :
Q1 = Q2
m1 . c1 . (T1-Tc)= m2 . c2 . (Tc-T2)
0,1Kg380 J/Kg0C . (900C-Tc0C)= 0,5kg . 4200 J/Kg0C . (Tc0C-100C)
38 J/Kg0C . (900C-Tc0C)= 2100J/0C  .(Tc0C-100C)
3420Kg0C-38kgTc0C= 2100kg Tc0C- 21000kg0C
3420Kg0C + 210000kgC = 2100kg Tc0C + 38kgTc0C
24420Kg0C = 2138Tc0kg
Tc = 24420Kg0C / 2138kg
Tc = 11,40C

 7. Diketahui : T2=100C
m2 = 250g = 0,25 Kg
T1=1000C
m1 = 200Kg = 0,2 Kg
c1,2 = 4200 J/Kg0C

Ditanya :
Tc=.....0C

Jawab :
Q1 = Q2
m1 . c1 . (T1-Tc)= m2 . c2 . (Tc-T2)
0,2Kg . 4200 J/Kg0C . (1000C-Tc0C)= 0,25kg . 4200 J/Kg0C . (Tc0C-100C)
0.2Kg . (1000C-Tc0C)= 0,25kg .(Tc0C-100C)
20Kg0C-0,2kgTc0C= 0,25kg Tc0C - 2,5kg0C
20Kg0C + 2,50kgC = 0,25kg Tc0C + 0,2kgTc0C
22,5Kg0C = 0,45Tc0kg
Tc = 22,5Kg0C / 0,45kg
Tc = 500C


 

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